Integrand size = 17, antiderivative size = 218 \[ \int \frac {\sqrt {c+d x}}{(a+b x)^6} \, dx=-\frac {\sqrt {c+d x}}{5 b (a+b x)^5}-\frac {d \sqrt {c+d x}}{40 b (b c-a d) (a+b x)^4}+\frac {7 d^2 \sqrt {c+d x}}{240 b (b c-a d)^2 (a+b x)^3}-\frac {7 d^3 \sqrt {c+d x}}{192 b (b c-a d)^3 (a+b x)^2}+\frac {7 d^4 \sqrt {c+d x}}{128 b (b c-a d)^4 (a+b x)}-\frac {7 d^5 \text {arctanh}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}\right )}{128 b^{3/2} (b c-a d)^{9/2}} \]
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Time = 0.10 (sec) , antiderivative size = 218, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.235, Rules used = {43, 44, 65, 214} \[ \int \frac {\sqrt {c+d x}}{(a+b x)^6} \, dx=-\frac {7 d^5 \text {arctanh}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}\right )}{128 b^{3/2} (b c-a d)^{9/2}}+\frac {7 d^4 \sqrt {c+d x}}{128 b (a+b x) (b c-a d)^4}-\frac {7 d^3 \sqrt {c+d x}}{192 b (a+b x)^2 (b c-a d)^3}+\frac {7 d^2 \sqrt {c+d x}}{240 b (a+b x)^3 (b c-a d)^2}-\frac {d \sqrt {c+d x}}{40 b (a+b x)^4 (b c-a d)}-\frac {\sqrt {c+d x}}{5 b (a+b x)^5} \]
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Rule 43
Rule 44
Rule 65
Rule 214
Rubi steps \begin{align*} \text {integral}& = -\frac {\sqrt {c+d x}}{5 b (a+b x)^5}+\frac {d \int \frac {1}{(a+b x)^5 \sqrt {c+d x}} \, dx}{10 b} \\ & = -\frac {\sqrt {c+d x}}{5 b (a+b x)^5}-\frac {d \sqrt {c+d x}}{40 b (b c-a d) (a+b x)^4}-\frac {\left (7 d^2\right ) \int \frac {1}{(a+b x)^4 \sqrt {c+d x}} \, dx}{80 b (b c-a d)} \\ & = -\frac {\sqrt {c+d x}}{5 b (a+b x)^5}-\frac {d \sqrt {c+d x}}{40 b (b c-a d) (a+b x)^4}+\frac {7 d^2 \sqrt {c+d x}}{240 b (b c-a d)^2 (a+b x)^3}+\frac {\left (7 d^3\right ) \int \frac {1}{(a+b x)^3 \sqrt {c+d x}} \, dx}{96 b (b c-a d)^2} \\ & = -\frac {\sqrt {c+d x}}{5 b (a+b x)^5}-\frac {d \sqrt {c+d x}}{40 b (b c-a d) (a+b x)^4}+\frac {7 d^2 \sqrt {c+d x}}{240 b (b c-a d)^2 (a+b x)^3}-\frac {7 d^3 \sqrt {c+d x}}{192 b (b c-a d)^3 (a+b x)^2}-\frac {\left (7 d^4\right ) \int \frac {1}{(a+b x)^2 \sqrt {c+d x}} \, dx}{128 b (b c-a d)^3} \\ & = -\frac {\sqrt {c+d x}}{5 b (a+b x)^5}-\frac {d \sqrt {c+d x}}{40 b (b c-a d) (a+b x)^4}+\frac {7 d^2 \sqrt {c+d x}}{240 b (b c-a d)^2 (a+b x)^3}-\frac {7 d^3 \sqrt {c+d x}}{192 b (b c-a d)^3 (a+b x)^2}+\frac {7 d^4 \sqrt {c+d x}}{128 b (b c-a d)^4 (a+b x)}+\frac {\left (7 d^5\right ) \int \frac {1}{(a+b x) \sqrt {c+d x}} \, dx}{256 b (b c-a d)^4} \\ & = -\frac {\sqrt {c+d x}}{5 b (a+b x)^5}-\frac {d \sqrt {c+d x}}{40 b (b c-a d) (a+b x)^4}+\frac {7 d^2 \sqrt {c+d x}}{240 b (b c-a d)^2 (a+b x)^3}-\frac {7 d^3 \sqrt {c+d x}}{192 b (b c-a d)^3 (a+b x)^2}+\frac {7 d^4 \sqrt {c+d x}}{128 b (b c-a d)^4 (a+b x)}+\frac {\left (7 d^4\right ) \text {Subst}\left (\int \frac {1}{a-\frac {b c}{d}+\frac {b x^2}{d}} \, dx,x,\sqrt {c+d x}\right )}{128 b (b c-a d)^4} \\ & = -\frac {\sqrt {c+d x}}{5 b (a+b x)^5}-\frac {d \sqrt {c+d x}}{40 b (b c-a d) (a+b x)^4}+\frac {7 d^2 \sqrt {c+d x}}{240 b (b c-a d)^2 (a+b x)^3}-\frac {7 d^3 \sqrt {c+d x}}{192 b (b c-a d)^3 (a+b x)^2}+\frac {7 d^4 \sqrt {c+d x}}{128 b (b c-a d)^4 (a+b x)}-\frac {7 d^5 \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}\right )}{128 b^{3/2} (b c-a d)^{9/2}} \\ \end{align*}
Time = 1.28 (sec) , antiderivative size = 224, normalized size of antiderivative = 1.03 \[ \int \frac {\sqrt {c+d x}}{(a+b x)^6} \, dx=\frac {\sqrt {c+d x} \left (-105 a^4 d^4+10 a^3 b d^3 (121 c+79 d x)+2 a^2 b^2 d^2 \left (-1052 c^2-289 c d x+448 d^2 x^2\right )+2 a b^3 d \left (744 c^3+128 c^2 d x-161 c d^2 x^2+245 d^3 x^3\right )+b^4 \left (-384 c^4-48 c^3 d x+56 c^2 d^2 x^2-70 c d^3 x^3+105 d^4 x^4\right )\right )}{1920 b (b c-a d)^4 (a+b x)^5}+\frac {7 d^5 \arctan \left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {-b c+a d}}\right )}{128 b^{3/2} (-b c+a d)^{9/2}} \]
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Time = 0.38 (sec) , antiderivative size = 220, normalized size of antiderivative = 1.01
method | result | size |
pseudoelliptic | \(\frac {-\frac {7 \sqrt {\left (a d -b c \right ) b}\, \left (\left (-b^{4} x^{4}-\frac {14}{3} a \,b^{3} x^{3}-\frac {128}{15} a^{2} b^{2} x^{2}-\frac {158}{21} a^{3} b x +a^{4}\right ) d^{4}-\frac {242 \left (-\frac {7}{121} b^{3} x^{3}-\frac {161}{605} a \,b^{2} x^{2}-\frac {289}{605} a^{2} b x +a^{3}\right ) b c \,d^{3}}{21}+\frac {2104 b^{2} c^{2} \left (-\frac {7}{263} b^{2} x^{2}-\frac {32}{263} a b x +a^{2}\right ) d^{2}}{105}-\frac {496 \left (-\frac {b x}{31}+a \right ) b^{3} c^{3} d}{35}+\frac {128 b^{4} c^{4}}{35}\right ) \sqrt {d x +c}}{128}+\frac {7 d^{5} \left (b x +a \right )^{5} \arctan \left (\frac {b \sqrt {d x +c}}{\sqrt {\left (a d -b c \right ) b}}\right )}{128}}{\sqrt {\left (a d -b c \right ) b}\, \left (b x +a \right )^{5} b \left (a d -b c \right )^{4}}\) | \(220\) |
derivativedivides | \(2 d^{5} \left (\frac {\frac {7 b^{3} \left (d x +c \right )^{\frac {9}{2}}}{256 \left (a^{4} d^{4}-4 a^{3} b c \,d^{3}+6 a^{2} b^{2} c^{2} d^{2}-4 a \,b^{3} c^{3} d +b^{4} c^{4}\right )}+\frac {49 b^{2} \left (d x +c \right )^{\frac {7}{2}}}{384 \left (a^{3} d^{3}-3 a^{2} b c \,d^{2}+3 a \,b^{2} c^{2} d -b^{3} c^{3}\right )}+\frac {7 b \left (d x +c \right )^{\frac {5}{2}}}{30 \left (a^{2} d^{2}-2 a b c d +b^{2} c^{2}\right )}+\frac {79 \left (d x +c \right )^{\frac {3}{2}}}{384 \left (a d -b c \right )}-\frac {7 \sqrt {d x +c}}{256 b}}{\left (\left (d x +c \right ) b +a d -b c \right )^{5}}+\frac {7 \arctan \left (\frac {b \sqrt {d x +c}}{\sqrt {\left (a d -b c \right ) b}}\right )}{256 b \left (a^{4} d^{4}-4 a^{3} b c \,d^{3}+6 a^{2} b^{2} c^{2} d^{2}-4 a \,b^{3} c^{3} d +b^{4} c^{4}\right ) \sqrt {\left (a d -b c \right ) b}}\right )\) | \(293\) |
default | \(2 d^{5} \left (\frac {\frac {7 b^{3} \left (d x +c \right )^{\frac {9}{2}}}{256 \left (a^{4} d^{4}-4 a^{3} b c \,d^{3}+6 a^{2} b^{2} c^{2} d^{2}-4 a \,b^{3} c^{3} d +b^{4} c^{4}\right )}+\frac {49 b^{2} \left (d x +c \right )^{\frac {7}{2}}}{384 \left (a^{3} d^{3}-3 a^{2} b c \,d^{2}+3 a \,b^{2} c^{2} d -b^{3} c^{3}\right )}+\frac {7 b \left (d x +c \right )^{\frac {5}{2}}}{30 \left (a^{2} d^{2}-2 a b c d +b^{2} c^{2}\right )}+\frac {79 \left (d x +c \right )^{\frac {3}{2}}}{384 \left (a d -b c \right )}-\frac {7 \sqrt {d x +c}}{256 b}}{\left (\left (d x +c \right ) b +a d -b c \right )^{5}}+\frac {7 \arctan \left (\frac {b \sqrt {d x +c}}{\sqrt {\left (a d -b c \right ) b}}\right )}{256 b \left (a^{4} d^{4}-4 a^{3} b c \,d^{3}+6 a^{2} b^{2} c^{2} d^{2}-4 a \,b^{3} c^{3} d +b^{4} c^{4}\right ) \sqrt {\left (a d -b c \right ) b}}\right )\) | \(293\) |
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Leaf count of result is larger than twice the leaf count of optimal. 830 vs. \(2 (186) = 372\).
Time = 0.27 (sec) , antiderivative size = 1673, normalized size of antiderivative = 7.67 \[ \int \frac {\sqrt {c+d x}}{(a+b x)^6} \, dx=\text {Too large to display} \]
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Timed out. \[ \int \frac {\sqrt {c+d x}}{(a+b x)^6} \, dx=\text {Timed out} \]
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Exception generated. \[ \int \frac {\sqrt {c+d x}}{(a+b x)^6} \, dx=\text {Exception raised: ValueError} \]
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Leaf count of result is larger than twice the leaf count of optimal. 432 vs. \(2 (186) = 372\).
Time = 0.32 (sec) , antiderivative size = 432, normalized size of antiderivative = 1.98 \[ \int \frac {\sqrt {c+d x}}{(a+b x)^6} \, dx=\frac {7 \, d^{5} \arctan \left (\frac {\sqrt {d x + c} b}{\sqrt {-b^{2} c + a b d}}\right )}{128 \, {\left (b^{5} c^{4} - 4 \, a b^{4} c^{3} d + 6 \, a^{2} b^{3} c^{2} d^{2} - 4 \, a^{3} b^{2} c d^{3} + a^{4} b d^{4}\right )} \sqrt {-b^{2} c + a b d}} + \frac {105 \, {\left (d x + c\right )}^{\frac {9}{2}} b^{4} d^{5} - 490 \, {\left (d x + c\right )}^{\frac {7}{2}} b^{4} c d^{5} + 896 \, {\left (d x + c\right )}^{\frac {5}{2}} b^{4} c^{2} d^{5} - 790 \, {\left (d x + c\right )}^{\frac {3}{2}} b^{4} c^{3} d^{5} - 105 \, \sqrt {d x + c} b^{4} c^{4} d^{5} + 490 \, {\left (d x + c\right )}^{\frac {7}{2}} a b^{3} d^{6} - 1792 \, {\left (d x + c\right )}^{\frac {5}{2}} a b^{3} c d^{6} + 2370 \, {\left (d x + c\right )}^{\frac {3}{2}} a b^{3} c^{2} d^{6} + 420 \, \sqrt {d x + c} a b^{3} c^{3} d^{6} + 896 \, {\left (d x + c\right )}^{\frac {5}{2}} a^{2} b^{2} d^{7} - 2370 \, {\left (d x + c\right )}^{\frac {3}{2}} a^{2} b^{2} c d^{7} - 630 \, \sqrt {d x + c} a^{2} b^{2} c^{2} d^{7} + 790 \, {\left (d x + c\right )}^{\frac {3}{2}} a^{3} b d^{8} + 420 \, \sqrt {d x + c} a^{3} b c d^{8} - 105 \, \sqrt {d x + c} a^{4} d^{9}}{1920 \, {\left (b^{5} c^{4} - 4 \, a b^{4} c^{3} d + 6 \, a^{2} b^{3} c^{2} d^{2} - 4 \, a^{3} b^{2} c d^{3} + a^{4} b d^{4}\right )} {\left ({\left (d x + c\right )} b - b c + a d\right )}^{5}} \]
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Time = 0.55 (sec) , antiderivative size = 401, normalized size of antiderivative = 1.84 \[ \int \frac {\sqrt {c+d x}}{(a+b x)^6} \, dx=\frac {\frac {79\,d^5\,{\left (c+d\,x\right )}^{3/2}}{192\,\left (a\,d-b\,c\right )}-\frac {7\,d^5\,\sqrt {c+d\,x}}{128\,b}+\frac {49\,b^2\,d^5\,{\left (c+d\,x\right )}^{7/2}}{192\,{\left (a\,d-b\,c\right )}^3}+\frac {7\,b^3\,d^5\,{\left (c+d\,x\right )}^{9/2}}{128\,{\left (a\,d-b\,c\right )}^4}+\frac {7\,b\,d^5\,{\left (c+d\,x\right )}^{5/2}}{15\,{\left (a\,d-b\,c\right )}^2}}{b^5\,{\left (c+d\,x\right )}^5-{\left (c+d\,x\right )}^2\,\left (-10\,a^3\,b^2\,d^3+30\,a^2\,b^3\,c\,d^2-30\,a\,b^4\,c^2\,d+10\,b^5\,c^3\right )-\left (5\,b^5\,c-5\,a\,b^4\,d\right )\,{\left (c+d\,x\right )}^4+a^5\,d^5-b^5\,c^5+{\left (c+d\,x\right )}^3\,\left (10\,a^2\,b^3\,d^2-20\,a\,b^4\,c\,d+10\,b^5\,c^2\right )+\left (c+d\,x\right )\,\left (5\,a^4\,b\,d^4-20\,a^3\,b^2\,c\,d^3+30\,a^2\,b^3\,c^2\,d^2-20\,a\,b^4\,c^3\,d+5\,b^5\,c^4\right )-10\,a^2\,b^3\,c^3\,d^2+10\,a^3\,b^2\,c^2\,d^3+5\,a\,b^4\,c^4\,d-5\,a^4\,b\,c\,d^4}+\frac {7\,d^5\,\mathrm {atan}\left (\frac {\sqrt {b}\,\sqrt {c+d\,x}}{\sqrt {a\,d-b\,c}}\right )}{128\,b^{3/2}\,{\left (a\,d-b\,c\right )}^{9/2}} \]
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